Question:
What is the domain of 2^x 2^y=1
Answer:
Given, 2x2 + 2y2 = 1
=> x2 + y2 = 1/2
=> x2 + y2 = (1/√2)2
This represents an equation of the circle whose radius is 1/√2, and it is centered at the
origin.
To find the domain, we just find the largest and smallest value of x.
Since the radius is 1/√2, and the graph is centered at the origin,
The largest x value is 1/√2
Similarly, the smallest x value is -1/√2
So, the domain is -1/√2 ≤ x ≤ 1/√2
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